TCS Coding Q-01

TCS NQT

Q. An automobile company manufactures both a two wheeler (TW) and a four wheeler (FW). A company manager wants to make the production of both types of vehicle according to the given data below:

1st data, Total number of vehicle (two-wheeler + four-wheeler)=v

2nd data, Total number of wheels = W

The task is to find how many two-wheelers as well as four-wheelers need to manufacture as per the given data.

C Program:

#include <stdio.h>

int main () 

{

  int v, w;

  v=100;

  w=300;

  int tw = ((4 * v) - w) / 2;

  if ((w & 1) || w < 2 || w <= v)

    {

      printf( "Invalide Input");

      return 0;

    }

printf("TW = %d ",tw);

printf("\n");

printf("FW = %d",v-tw);

}

Output:

TW = 50 

FW = 50

C++ Program:

#include <iostream>

using namespace std;

int main () 

{

  int v, w;

  v=100;

  w=300;

  //cin >> v >> w;

  float tw = ((4 * v) - w) / 2;

  if ((w & 1) || w < 2 || w <= v)

    {

      cout << "Invalide Input";

      return 0;

    }

cout << "TW=" << tw << " " << "FW=" << v - tw;

}

Output:

TW=50 FW=50